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Q. Gravitational potential $V$ versus distance $r$ graph is represented in the figure. The magnitude of gravitational field intensity is equal to

Question

NTA AbhyasNTA Abhyas 2020Gravitation

Solution:

$|\vec{E}|=\frac{\Delta V}{\Delta r}=\frac{8-4}{(1) \sin 30^{\circ}}=8 \mathrm{Nkg}^{-1}$