Question

Gold number of haemoglobin is $0.03$. Hence $100ml$ of gold sol will require haemoglobin so that gold is not coagulated by $10ml$ of $10\%NaCl$ solution -

Answer 1

Answer: 0.30

Gold number
$=\frac{\text{ weight of lyophilic sol in }mg}{\text{ Volume of gold sol in }ml}\times 10$
$\Rightarrow 0.03=\frac{\text{ weight of lyophilic sol in }mg}{100}\times 10$
$\Rightarrow$ weight of lyophilic sol in $mg=0.3$
$\therefore$ weight $=0.3mg$