Given the standard reduction potentials Zn2+/Zn=-0.74 V, Cl2/Cl-=1.36 V, H+/1/2H2=0 V and Fe2+/Fe3+=0.77 V The order of increasing strength as reducing agent is:

Question

Given the standard reduction potentials Zn2+/Zn=-0.74 V, Cl2/Cl-=1.36 V, H+/1/2H2=0 V and Fe2+/Fe3+=0.77 V The order of increasing strength as reducing agent is: (A)  Cl-,Zn,H2,Fe2+  (B)  H2,Zn,Fe2+,Cl  (C)  Cl-Fe2+,Zn,H2  (D)  H2Fe2+,Cl-,Zn

Tardigrade Admin · Accepted Answer

The substances which have lower reduction potentials are stronger reducing agents. Hence the order of strength of reducing agent is increases in the following order:

Cl < F e^{2 +} < H_{2} < Z n s t re n g t h o f re d u c in g a g e n t - in cre a ses

Q. Given the standard reduction potentials $Z n^{2 +} / Z n = - 0.74 V,$ $C l_{2} / C l^{-} = 1.36 V,$ $H^{+} /1/2 H_{2} = 0 V$ and $F e^{2 +} / F e^{3 +} = 0.77 V$
The order of increasing strength as reducing agent is:

$C l^{-}, Z n, H_{2}, F e^{2 +}$

$H_{2}, Z n, F e^{2 +}, Cl$

$C l^{-} F e^{2 +}, Z n, H_{2}$

$H_{2} F e^{2 +}, C l^{-}, Z n$

$C l^{-}, F e^{2 +}, H_{2}, Z n$

The substances which have lower reduction potentials are stronger reducing agents. Hence the order of strength of reducing agent is increases in the following order:
$Cl < F e^{2 +} < H_{2} < Z n s t re n g t h o f re d u c in g a g e n t - in cre a ses$

Q. Given the standard reduction potentials Zn2+/Zn=−0.74V, Cl2​/Cl−=1.36V, H+/1/2H2​=0V and Fe2+/Fe3+=0.77V The order of increasing strength as reducing agent is:

Cl−,Zn,H2​,Fe2+

H2​,Zn,Fe2+,Cl

Cl−Fe2+,Zn,H2​

H2​Fe2+,Cl−,Zn

Cl−,Fe2+,H2​,Zn

The substances which have lower reduction potentials are stronger reducing agents. Hence the order of strength of reducing agent is increases in the following order: Cl<Fe2+<H2​<Znstrengthofreducingagent−increases​