Given the molecular formula of the hexacoordinated complexes (A) [Co Cl3.6NH3] (B) [Co Cl3.5NH3] (C) CoCl3.4NH3. If the number of coordinated NH3 molecules in A, B and C respectively are 6, 5 and 4, the primary valency in (A), (B) and (C) are:

Question

Given the molecular formula of the hexacoordinated complexes (A) [Co Cl3.6NH3] (B) [Co Cl3.5NH3] (C) CoCl3.4NH3. If the number of coordinated NH3 molecules in A, B and C respectively are 6, 5 and 4, the primary valency in (A), (B) and (C) are: (A) 6, 5 ,4 (B) 3 ,2 , 1 (C) 0 ,1 ,2 (D) 3, 3, 3

Tardigrade Admin · Accepted Answer

The complexes can be written as follows underset(A)[Co(NH3)6]Cl3 underset(B)[Co(NH3)5Cl]Cl2 underset(C)[Co (NH3)4Cl4]Cl Hence, number of primary valencies are 3, 2 and 1 respectively

$6, 5, 4$

$3, 2, 1$

$0, 1, 2$

$3, 3, 3$

The complexes can be written as follows
$(A) [C o (N H_{3})_{6}] C l_{3} (B) [C o (N H_{3})_{5} Cl] C l_{2} (C) [C o (N H_{3})_{4} C l_{4}] Cl$
Hence, number of primary valencies are 3, 2 and 1 respectively

Q. Given the molecular formula of the hexacoordinated complexes (A) [CoCl3​.6NH3​] (B) [CoCl3​.5NH3​] (C) CoCl3​.4NH3​. If the number of coordinated NH3​ molecules in A,B and C respectively are 6,5 and 4, the primary valency in (A), (B) and (C) are:

6,5,4

3,2,1

0,1,2

3,3,3

The complexes can be written as follows (A)[Co(NH3​)6​]Cl3​​(B)[Co(NH3​)5​Cl]Cl2​​(C)[Co(NH3​)4​Cl4​]Cl​ Hence, number of primary valencies are 3, 2 and 1 respectively

$6, 5, 4$

$3, 2, 1$

$0, 1, 2$

$3, 3, 3$

The complexes can be written as follows
$(A) [C o (N H_{3})_{6}] C l_{3} (B) [C o (N H_{3})_{5} Cl] C l_{2} (C) [C o (N H_{3})_{4} C l_{4}] Cl$
Hence, number of primary valencies are 3, 2 and 1 respectively