Question

Given the following reactions involving $A,B,C$ and $D$
(i) $C+B^{+}\to C^{+}+B$
(ii) $A^{+}+D\to$ No reaction
(iii) $C^{+}+A\to$ No reaction
(iv) $D+B^{+}\to D^{+}+B$
The correct arrangement of $A,B,C,D$ in order of their decreasing ability as reducing agent

• A. D > B > C > A
• B. A > C > D > B
• C. C > A > B > D
• D. C > A > D > B

Answer 1

Answer: (D)

$C+B^{+}\to C^{+}+B;$
$\therefore C>B$ (reducing power)
$A^{+}+D\to$ No reaction;
$\therefore A>D$ (reducing power)
$C^{+}+A\to$ No reaction;
$\therefore C>A$ (reducing power)
$D+B^{+}\to D^{+}+B;$
$\therefore D>B$ (reducing power)
Hence, order of reducing power
$=C>A>D>B$