Given that R is Rydbergs constant. When an electron in an atom of hydrogen jumps from an outer orbit n = 3 to an inner orbit n = 2, the wavelength of emitted radiations will be equal to :

Question

Given that R is Rydbergs constant. When an electron in an atom of hydrogen jumps from an outer orbit n = 3 to an inner orbit n = 2, the wavelength of emitted radiations will be equal to : (A) λ=(R/62) (B) λ=(62/R) (C) λ=(5R/36) (D) λ=(36/5R)

Tardigrade Admin · Accepted Answer

(1/λ) = R ( (1/n12) - (1/n2g) )

Q. Given that R is Rydbergs constant. When an electron in an atom of hydrogen jumps from an outer orbit n = 3 to an inner orbit n = 2, the wavelength of emitted radiations will be equal to :

$λ = \frac{R}{6 ^{2}}$

$λ = \frac{6 ^{2}}{R}$

$λ = \frac{5 R}{36}$

$λ = \frac{36}{5 R}$

$\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{g}^{2}})$

Q. Given that R is Rydbergs constant. When an electron in an atom of hydrogen jumps from an outer orbit n = 3 to an inner orbit n = 2, the wavelength of emitted radiations will be equal to :

λ=62R​

λ=R62​

λ=365R​

λ=5R36​

λ1​=R(n12​1​−ng2​1​)

$λ = \frac{R}{6 ^{2}}$

$λ = \frac{6 ^{2}}{R}$

$λ = \frac{5 R}{36}$

$λ = \frac{36}{5 R}$

$\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{g}^{2}})$