Q. Given that : $N_{2} (g) \to 2 N (g); (Δ H)_{1}$
$C l_{2} (g) \to 2 Cl (g); Δ H_{2}$
$NC l_{3} (g) \to N + 3 Cl; Δ H_{3}$
The heat of formation of $NC l_{3} (g)$ is :-

72 185 NTA AbhyasNTA Abhyas 2022 Report Error

A

$Δ H_{1} + 3Δ H_{2} - 2Δ H_{3}$

B

$2Δ H_{3} - Δ H_{1} - 3Δ H_{2}$

C

$Δ H_{3} - \frac{1}{2} Δ H_{1} - \frac{3}{2} Δ H_{2}$

D

$\frac{1}{2} Δ H_{1} + \frac{3}{2} Δ H_{2} - Δ H_{3}$

Solution:

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