Given that: E O 2 H 2 O °=+1 ⋅ 23 V E S 2 O 82-/ SO 42-° =+2 ⋅ 05 V E Br 2 / Br -°=+1 ⋅ 09 V E Au 3 / Au °=+1 ⋅ 4 V The strongest oxidizing agent is -

Question

Given that: E O 2 H 2 O °=+1 ⋅ 23 V E S 2 O 82-/ SO 42-° =+2 ⋅ 05 V E Br 2 / Br -°=+1 ⋅ 09 V E Au 3 / Au °=+1 ⋅ 4 V The strongest oxidizing agent is - (A) O2 (B) Br2 (C) S2O82- (D) Au3+

Tardigrade Admin · Accepted Answer

For strongest oxidising agent, standard reduction potential should be highest.

Q. Given that : $E_{O_{2} H_{2} O}^{\circ} = + 1 \cdot 23 V$
$E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{\circ} = + 2 \cdot 05 V$
$E_{B r_{2} / B r^{-}}^{\circ} = + 1 \cdot 09 V$
$E_{A u^{3} / A u}^{\circ} = + 1 \cdot 4 V$
The strongest oxidizing agent is -

$O_{2}$

$B r_{2}$

$S_{2} O_{8}^{2 -}$

$A u^{3 +}$

For strongest oxidising agent, standard reduction potential should be highest.

Q. Given that : EO2​H2​O∘​=+1⋅23V ES2​O82−​/SO42−​∘​=+2⋅05V EBr2​/Br−∘​=+1⋅09V EAu3/Au∘​=+1⋅4V The strongest oxidizing agent is -

O2​

Br2​

S2​O82−​

Au3+

For strongest oxidising agent, standard reduction potential should be highest.

Q. Given that : $E_{O_{2} H_{2} O}^{\circ} = + 1 \cdot 23 V$
$E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{\circ} = + 2 \cdot 05 V$
$E_{B r_{2} / B r^{-}}^{\circ} = + 1 \cdot 09 V$
$E_{A u^{3} / A u}^{\circ} = + 1 \cdot 4 V$
The strongest oxidizing agent is -

$O_{2}$

$B r_{2}$

$S_{2} O_{8}^{2 -}$

$A u^{3 +}$