Given that 50.0 mL of 0.01 M Na 2 S 2 O 3 solution and 5 × 10-4 mole of Cl 2 react according to equation, Cl 2 (g) + S 2 O 32- longrightarrow SO 42-+ Cl -+ S Answer the following: The balanced molecular equation is :

Question

Given that 50.0 mL of 0.01 M Na 2 S 2 O 3 solution and 5 × 10-4 mole of Cl 2 react according to equation, Cl 2 (g) + S 2 O 32- longrightarrow SO 42-+ Cl -+ S Answer the following: The balanced molecular equation is : (A) Cl 2+ H 2 O + Na 2 S 2 O 3 arrow Na 2 SO 4+ S +2 HCl (B) Cl 2+ Na 2 S 2 O 3 arrow 2 NaCl + Na 2 SO 4 (C) Cl 2+ S 2 O 32- arrow SO 42-+ S + Cl - (D) None of the above

Tardigrade Admin · Accepted Answer

Correct answer is (a) Cl 2+ H 2 O + Na 2 S 2 O 3 arrow Na 2 SO 4+ S +2 HCl

Q. Given that $50.0 m L$ of $0.01 MN a_{2} S_{2} O_{3}$ solution and $5 \times 1 0^{- 4}$ mole of $C l_{2}$ react according to equation, $C l_{2}$ (g) $+$ $S_{2} O_{3}^{2 -} ⟶ S O_{4}^{2 -} + C l^{-} + S$
Answer the following :
The balanced molecular equation is :

$C l_{2} + H_{2} O + N a_{2} S_{2} O_{3} \to N a_{2} S O_{4} + S + 2 H Cl$

$C l_{2} + N a_{2} S_{2} O_{3} \to 2 N a Cl + N a_{2} S O_{4}$

$C l_{2} + S_{2} O_{3}^{2 -} \to S O_{4}^{2 -} + S + C l^{-}$

None of the above

Correct answer is (a) $C l_{2} + H_{2} O + N a_{2} S_{2} O_{3} \to N a_{2} S O_{4} + S + 2 H Cl$

Q. Given that 50.0mL of 0.01MNa2​S2​O3​ solution and 5×10−4 mole of Cl2​ react according to equation, Cl2​ (g) + S2​O32−​⟶SO42−​+Cl−+S Answer the following : The balanced molecular equation is :

Cl2​+H2​O+Na2​S2​O3​→Na2​SO4​+S+2HCl

Cl2​+Na2​S2​O3​→2NaCl+Na2​SO4​

Cl2​+S2​O32−​→SO42−​+S+Cl−