Given standard enthalpy of formation of CO and CO 2 are (-110 kJ mol -1) and (-394 kJ mol -1) respectively. The heat of combustion when one mole of graphite burns is

Question

Given standard enthalpy of formation of CO and CO 2 are (-110 kJ mol -1) and (-394 kJ mol -1) respectively. The heat of combustion when one mole of graphite burns is (A) -110 kJ (B) -284 kJ (C) -394 kJ (D) -504 kJ

Tardigrade Admin · Accepted Answer

Combustion of graphite, C + O 2 arrow CO 2 Δ H=-394 kJ mol -1= heat of formation of CO 2

Q. Given standard enthalpy of formation of $CO$ and $C O_{2}$ are $(- 110 k J m o l^{- 1})$ and $(- 394 k J m o l^{- 1})$ respectively. The heat of combustion when one mole of graphite burns is

$- 110 k J$

$- 284 k J$

$- 394 k J$

$- 504 k J$

Combustion of graphite, $C + O_{2} \to C O_{2}$

$Δ H = - 394 k J m o l^{- 1} =$ heat of formation of $C O_{2}$

Q. Given standard enthalpy of formation of CO and CO2​ are (−110kJmol−1) and (−394kJmol−1) respectively. The heat of combustion when one mole of graphite burns is

−110kJ

−284kJ

−394kJ

−504kJ