Given standard electrode potentials Fe 2:+2 e - longrightarrow Fe E °=-0 ⋅ 440 V Fe 3++3 e - longrightarrow Fe E °=-0 ⋅ 036 V The standard electrode potential (E°) for Fe 3++ e - longrightarrow Fe 2+ is :

Question

Given standard electrode potentials Fe 2:+2 e - longrightarrow Fe E °=-0 ⋅ 440 V Fe 3++3 e - longrightarrow Fe E °=-0 ⋅ 036 V The standard electrode potential (E°) for Fe 3++ e - longrightarrow Fe 2+ is : (A) + 0.772 V (B) - 0.772 V (C) + 0.417 V (D) -0.414 V

Tardigrade Admin · Accepted Answer

We know, triangle G °=- nFE ° Fe 2++2 e - arrow Fe Δ G °=-2 × F ×(-0.440 V )=0.880 F ... (1) Fe 3++3 e - arrow Fe Δ G °=-3 × F ×(-0.036)=0.108 F ... -(2) On subtracting Eqs. (1) from (2), Fe 3++ e - arrow Fe 2+ Δ G °=0.108 F -0.880 F =-0.772 F Δ G °=- nFE ° E °=(Δ G °/- nF )=(-0.772 F /-1 × F )=+0.772 V

Q. Given standard electrode potentials Fe2:+2e−⟶FeE∘=−0⋅440V Fe3++3e−⟶FeE∘=−0⋅036V The standard electrode potential (E∘) for Fe3++e−⟶Fe2+ is :

+ 0.772 V

- 0.772 V

+ 0.417 V

-0.414 V

We know, △G∘=−nFE∘ Fe2++2e−→Fe ΔG∘=−2×F×(−0.440V)=0.880F... (1) Fe3++3e−→Fe ΔG∘=−3×F×(−0.036)=0.108F... -(2) On subtracting Eqs. (1) from (2), Fe3++e−→Fe2+ ΔG∘=0.108F−0.880F=−0.772F ΔG∘=−nFE∘ E∘=−nFΔG∘​=−1×F−0.772F​=+0.772V

Q. Given standard electrode potentials
$F e^{2} : + 2 e^{-} ⟶ F e E^{\circ} = - 0 \cdot 440 V$
$F e^{3 +} + 3 e^{-} ⟶ F e E^{\circ} = - 0 \cdot 036 V$
The standard electrode potential $(E^{\circ})$ for
$F e^{3 +} + e^{-} ⟶ F e^{2 +}$ is :