Given pH of a solution A is 3 and it is mixed with another solution B having pH 2. If both mixed, then resultant pH of the solution will be :

Question

Given pH of a solution A is 3 and it is mixed with another solution B having pH 2. If both mixed, then resultant pH of the solution will be : (A) 3.2 (B) 1.9 (C) 3.4 (D) 3.5

Tardigrade Admin · Accepted Answer

pH of A=3 pH of B=2 ∴ [ H +]=10-3 M, [ H +]=10-2 M Total [ H +] =10-3+10-2=10-3+10 × 10-3 =11 × 10-3 ∴ pH =- log 10[ H +]=- log (11 × 10-3) =3- log 11 =3-1.04=1.96

Q. Given $p H$ of a solution $A$ is $3$ and it is mixed with another solution $B$ having $p H$ 2. If both mixed, then resultant pH of the solution will be :

3.2

1.9

3.4

3.5

$p H$ of $A = 3 p H$ of $B = 2$
$∴ [H^{+}] = 1 0^{- 3} M, [H^{+}] = 1 0^{- 2} M$
Total $[H^{+}]$
$= 1 0^{- 3} + 1 0^{- 2} = 1 0^{- 3} + 10 \times 1 0^{- 3}$
$= 11 \times 1 0^{- 3}$
$∴ p H = - lo g_{10} [H^{+}] = - lo g (11 \times 1 0^{- 3})$
$= 3 - lo g 11$
$= 3 - 1.04 = 1.96$

Q. Given pH of a solution A is 3 and it is mixed with another solution B having pH 2. If both mixed, then resultant pH of the solution will be :

3.2

1.9

3.4

3.5

pH of A=3pH of B=2 ∴[H+]=10−3M,[H+]=10−2M Total [H+] =10−3+10−2=10−3+10×10−3 =11×10−3 ∴pH=−log10​[H+]=−log(11×10−3) =3−log11 =3−1.04=1.96

Q. Given $p H$ of a solution $A$ is $3$ and it is mixed with another solution $B$ having $p H$ 2. If both mixed, then resultant pH of the solution will be :

$p H$ of $A = 3 p H$ of $B = 2$
$∴ [H^{+}] = 1 0^{- 3} M, [H^{+}] = 1 0^{- 2} M$
Total $[H^{+}]$
$= 1 0^{- 3} + 1 0^{- 2} = 1 0^{- 3} + 10 \times 1 0^{- 3}$
$= 11 \times 1 0^{- 3}$
$∴ p H = - lo g_{10} [H^{+}] = - lo g (11 \times 1 0^{- 3})$
$= 3 - lo g 11$
$= 3 - 1.04 = 1.96$