Given (I) 2 Fe 2 O 3( s ) → 4 Fe ( s )+3 O 2( g ) ; Δr G°=+1487.0 kJ mol-1 (II) 2 CO ( g )+ O 2( g ) arrow 2 CO 2( g ) ; Δr, G°=-514.4 kJ mol -1 Free energy change, Δr G° for the reaction 2 Fe 2 O 3( s )+ 6 CO ( g ) arrow 4 Fe ( s )+6 CO 2( g ) will be

Question

Given (I) 2 Fe 2 O 3( s ) → 4 Fe ( s )+3 O 2( g ) ; Δr G°=+1487.0 kJ mol-1 (II) 2 CO ( g )+ O 2( g ) arrow 2 CO 2( g ) ; Δr, G°=-514.4 kJ mol -1 Free energy change, Δr G° for the reaction 2 Fe 2 O 3( s )+ 6 CO ( g ) arrow 4 Fe ( s )+6 CO 2( g ) will be (A) - 112.4 kJ mol-1 (B) - 56.2 kJ mol-1 (C)  - 168.2 kJ mol-1 (D)  - 208.0 kJ mol-1

Tardigrade Admin · Accepted Answer

We have 2Fe 2 O 3( s ) arrow 4 Fe ( s )+3 O 2( g ) ; Δr G°=+1487.0 kJ mol -1 2 CO ( g )+ O 2( g ) arrow 2 CO 2( g ) ; Δr G°=-514.4 kJ mol -1 Δr G° for the reaction 2 Fe 2 O 3( s )+6 CO ( g ) arrow 4 Fe ( s )+6 CO 2( g ) can be obtained by Eq. (1) +3 × Eq .(2) Δ G° =1487.0+3 ×(-514.4) =1487-1543.2 =-56.2 kJ mol -1

$- 112.4 k J m o l^{- 1}$

$- 56.2 k J m o l^{- 1}$

$- 168.2 k J m o l^{- 1}$

$- 208.0 k J m o l^{- 1}$

Q. Given (I) 2Fe2​O3​(s)→4Fe(s)+3O2​(g);Δr​G∘=+1487.0kJmol−1 (II) 2CO(g)+O2​(g)→2CO2​(g);Δr​,G∘=−514.4kJmol−1 Free energy change, Δr​G∘ for the reaction 2Fe2​O3​(s)+6CO(g)→4Fe(s)+6CO2​(g) will be

−112.4kJmol−1

−56.2kJmol−1

−168.2kJmol−1

−208.0kJmol−1

$- 112.4 k J m o l^{- 1}$

$- 56.2 k J m o l^{- 1}$

$- 168.2 k J m o l^{- 1}$

$- 208.0 k J m o l^{- 1}$