Given: E° Fe 3+ / Fe =-0.036 V , E° Fe 2+ / Fe =-0.439 V. The value of standard electrode potential for the change, Fe (a q)3++e- arrow Fe 2+ (a q) will be

Question

Given: E° Fe 3+ / Fe =-0.036 V , E° Fe 2+ / Fe =-0.439 V. The value of standard electrode potential for the change, Fe (a q)3++e- arrow Fe 2+ (a q) will be (A) -0.072 V (B) 0.385 V (C) 0.770 V (D) -0.270 V

Tardigrade Admin · Accepted Answer

Given, Fe 3++3 e- longrightarrow Fe ; E° 1=-0.036 V Fe 2++2 e- longrightarrow Fe ; E° 2=-0.439 V Required equation is Fe 3++e- longrightarrow Fe 2+ ; E3°=? Applying, Δ G°=-n F E° ∴ Δ G3°=Δ G1°-Δ G2° (-n3 F E° 3)=(-n1 F E° 1)-(-n2 F E2°) E3°=3 E1°-2 E2°=3 ×(-0.036)-2 ×(-0.439) E3°=-0.108+0.878=0.77 V

Q. Given $: E_{F e^{3 +} / F e}^{\circ} = - 0.036 V, E_{F e^{2 +} / F e}^{\circ} = - 0.439 V$ . The value of standard electrode potential for the change, $F e_{(a q)}^{3 +} + e^{-} \to F e^{2 +}_{(a q)}$ will be

$- 0.072 V$

$0.385 V$

$0.770 V$

$- 0.270 V$

Q. Given :EFe3+/Fe∘​=−0.036V,EFe2+/Fe∘​=−0.439V. The value of standard electrode potential for the change, Fe(aq)3+​+e−→Fe2+(aq)​ will be

−0.072V

0.385V

0.770V

−0.270V

Q. Given $: E_{F e^{3 +} / F e}^{\circ} = - 0.036 V, E_{F e^{2 +} / F e}^{\circ} = - 0.439 V$ . The value of standard electrode potential for the change, $F e_{(a q)}^{3 +} + e^{-} \to F e^{2 +}_{(a q)}$ will be

$- 0.072 V$

$0.385 V$

$0.770 V$

$- 0.270 V$