Given a triangle A B C with unequal sides. P is the set of all points which is equidistant from B C and Q is the set of all point which is equidistant from sides A B and A C. Then n(P ∪ Q) equals :

Question

Given a triangle A B C with unequal sides. P is the set of all points which is equidistant from B C and Q is the set of all point which is equidistant from sides A B and A C. Then n(P ∪ Q) equals : (A) 1 (B) 2 (C) 3 (D) Infinite

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/10bba5aaabcf37f162af56d721dd1e82-.png" /> P lies on line AD; Q lies on EM

Q. Given a $△ A BC$ with unequal sides. $P$ is the set of all points which is equidistant from $B & C$ and $Q$ is the set of all point which is equidistant from sides $A B$ and $A C$ . Then $n (P \cup Q)$ equals :

1

2

3

Infinite

$P$ lies on line $A D; Q$ lies on $EM$

Q. Given a △ABC with unequal sides. P is the set of all points which is equidistant from B&C and Q is the set of all point which is equidistant from sides AB and AC. Then n(P∪Q) equals :

1

2

3

Infinite

P lies on line AD;Q lies on EM

Q. Given a $△ A BC$ with unequal sides. $P$ is the set of all points which is equidistant from $B & C$ and $Q$ is the set of all point which is equidistant from sides $A B$ and $A C$ . Then $n (P \cup Q)$ equals :

$P$ lies on line $A D; Q$ lies on $EM$