Question

Give the IUPAC name of $[Pt(N{H}_3{)}_4]$ $[PtC{l}_4]$ is

• A. Tetra ammine platinum (I) tetra chlorido platinum (IV)
• B. Tetra ammine palatinate (II) tetra chlorido platinum (II)
• C. Tetra ammine palatinate (o) tetra chlorido platinum (IV)
• D. Tetra ammine platinum (II) tetra chlorido palatinate (II)

Answer 1

Answer: (D)

$N{H}_3$ is neutral, making the first complex positively charged overall.
$Cl$ has a $-1$ charge, making the second complex the anion and so platinum ends with -ate.
Therefore, the complex with $N{H}_3$ comes first, followed by the one with $Cl$.
Option (A) is correct. The I.U.P.A.C name for $\left[Pt{\left(N{H}_3\right)}_4\right]\left[PtC{l}_4\right]$
is tetraammineplatinum(II) tetrachloridoplatinate(II)