Give reason for the statement. ‘[Ni(CN)4]2- is diamagnetic while [NiCl4]2- is paramagnetic in nature.’

Question

Give reason for the statement. ‘[Ni(CN)4]2- is diamagnetic while [NiCl4]2- is paramagnetic in nature.’ (A) In [NiCl4]2-, no unpaired electrons are present while in [Ni(CN)4]2- two unpaired electrons are present (B) In [Ni(CN)4]2-, no unpaired electrons are present while in [NiCl4]2- two unpaired electrons are present (C) [NiCl4]2- shows dsp2 hybridisation hence it is paramagnetic (D) [Ni(CN)4]2- shows sp3 hybridisation hence it is diamagnetic

Tardigrade Admin · Accepted Answer

In [Ni(CN)4]2- there is no unpaired electrons because CN- is a strong field ligand. Therefore it is diamagnetic in nature.

In [NiCl4]2-, there are two unpaired electrons because Cl- is a weak field ligand. Therefore, it is paramagnetic in nature.

Q. Give reason for the statement. $‘ [N i (CN)_{4}]^{2 -}$ is diamagnetic while $[N i C l_{4}]^{2 -}$ is paramagnetic in nature.’

In $[N i C l_{4}]^{2 -}$ , no unpaired electrons are present while in $[N i (CN)_{4}]^{2 -}$ two unpaired electrons are present

In $[N i (CN)_{4}]^{2 -}$ , no unpaired electrons are present while in $[N i C l_{4}]^{2 -}$ two unpaired electrons are present

$[N i C l_{4}]^{2 -}$ shows $d s p^{2}$ hybridisation hence it is paramagnetic

$[N i (CN)_{4}]^{2 -}$ shows $s p^{3}$ hybridisation hence it is diamagnetic

In $[N i (CN)_{4}]^{2 -}$ there is no unpaired electrons because $C N^{-}$ is a strong field ligand. Therefore it is diamagnetic in nature.

In $[N i C l_{4}]^{2 -}$ , there are two unpaired electrons because $C l^{-}$ is a weak field ligand. Therefore, it is paramagnetic in nature.

Q. Give reason for the statement. ‘[Ni(CN)4​]2− is diamagnetic while [NiCl4​]2− is paramagnetic in nature.’

In [NiCl4​]2−, no unpaired electrons are present while in [Ni(CN)4​]2− two unpaired electrons are present

In [Ni(CN)4​]2−, no unpaired electrons are present while in [NiCl4​]2− two unpaired electrons are present

[NiCl4​]2− shows dsp2 hybridisation hence it is paramagnetic

[Ni(CN)4​]2− shows sp3 hybridisation hence it is diamagnetic