Geostationary satellite orbits around the earth in a circular orbit of radius 36000 km. Then the time period of a spy satellite orbiting a 500 km above the earths surface (radius of earth = 6400 km) will approximately be

Question

Geostationary satellite orbits around the earth in a circular orbit of radius 36000 km. Then the time period of a spy satellite orbiting a 500 km above the earths surface (radius of earth = 6400 km) will approximately be (A)  (1/2)h  (B)  1 h  (C)  2 h  (D)  4 h

Tardigrade Admin · Accepted Answer

T2=T1( (r2/r1) )3/2 =24( (6400/36000) )3/2 =1.7h For spy satellite h is slightly greater than Re . So, T1>T2 hence, Ts=2h

Q. Geostationary satellite orbits around the earth in a circular orbit of radius 36000 km. Then the time period of a spy satellite orbiting a 500 km above the earths surface (radius of earth = 6400 km) will approximately be

$\frac{1}{2} h$

$1 h$

$2 h$

$4 h$

$T_{2} = T_{1} (\frac{r _{2}}{r _{1}})^{3/2}$ $= 24 (\frac{6400}{36000})^{3/2}$ $= 1.7 h$ For spy satellite h is slightly greater than $R_{e}$ . So, $T_{1} > T_{2}$ hence, $T_{s} = 2 h$