Geometrical isomerism is not shown by

Question

Geometrical isomerism is not shown by (A) 1,1-dichloro-1-pentene (B) 1,2-dichloro-1-pentene (C) 1,3-dichloro-2-pentene (D) 1,4-dichloro-2-pentene.

Tardigrade Admin · Accepted Answer

A compound containing a double bond can show geometrical isomerism only when identical groups are not present on the double bonded carbon. 1,1-dichloro-1-pentene, i.e. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/39c3f35fafe5139ca8ffd18385490977-.png" /> cannot show geometrical isomerism because on C-l identical groups (Cl ) are present.

Q. Geometrical isomerism is not shown by

$1, 1$ -dichloro- $1$ -pentene

$1, 2$ -dichloro- $1$ -pentene

$1, 3$ -dichloro- $2$ -pentene

$1, 4$ -dichloro- $2$ -pentene.

A compound containing a double bond can show geometrical isomerism only when identical groups are not present on the double bonded carbon. $1, 1 -$ dichloro- $1$ -pentene, i.e.

cannot show geometrical isomerism because on $C - l$ identical groups ( $Cl$ ) are present.

Q. Geometrical isomerism is not shown by

1,1-dichloro-1-pentene

1,2-dichloro-1-pentene

1,3-dichloro-2-pentene

1,4-dichloro-2-pentene.

A compound containing a double bond can show geometrical isomerism only when identical groups are not present on the double bonded carbon. 1,1−dichloro-1-pentene, i.e. cannot show geometrical isomerism because on C−l identical groups (Cl ) are present.

$1, 1$ -dichloro- $1$ -pentene

$1, 2$ -dichloro- $1$ -pentene

$1, 3$ -dichloro- $2$ -pentene

$1, 4$ -dichloro- $2$ -pentene.

A compound containing a double bond can show geometrical isomerism only when identical groups are not present on the double bonded carbon. $1, 1 -$ dichloro- $1$ -pentene, i.e.

cannot show geometrical isomerism because on $C - l$ identical groups ( $Cl$ ) are present.