Question

General formula of solid in zinc blende structure is:

• A. $A{B}_2$
• B. $A{B}_4$
• C. $AB$
• D. $A_{2}B$

Answer 1

Answer: (C)

$Z{n}^{+2}$ present in alternate tetrahedral void
$=\frac{1}{2}\times 8=4$
$S^{2-}$ present in $ccp=4$
$\therefore Z{n}_4{S}_4=ZnS$ i.e., $AB$ type compound.