Consider the case when Ge and Si diodes are connected as show in the given figure.
Equivalent voltage drop across the combination Ge and Si diode =0.3V ⇒ Current i=5kΩ12−0.3=2.34mA ∴ Output voltage V0=Ri=5kΩ2.34mA=11.7V
Now consider the case when diode connection are reversed. In this case voltage drop across the diode's combination =0.7V ⇒ Current i=5kΩ12−0.7=2.26mA ∴V0=iR=2.26mA×5kΩ=11.3V
Hence charge in the value of V0=11.7−11.3=0.4V