Ge & Si diodes conduct at knee voltage 0.3V & 0.7V respectively. If Ge diode connection are reversed, then value of V0 changes by xV , what is the value of 10x ?

Question

Ge & Si diodes conduct at knee voltage 0.3V & 0.7V respectively. If Ge diode connection are reversed, then value of V0 changes by xV , what is the value of 10x ? <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-uaseumahrln8uaiq.jpg" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Initially only Ge will work i=(15 . 2/8)(V0)i=(15 . 2/8)× 6 Finally only Si will work i=(14 . 8/8)(V0)f=(14 . 8/8)× 6 Change =(0 . 4/8)× 6=0.3V

Q. Ge & Si diodes conduct at knee voltage $0.3 V$ & $0.7 V$ respectively. If Ge diode connection are reversed, then value of $V_{0}$ changes by $x V$ , what is the value of $10 x$ ?

Initially only Ge will work $i = \frac{15.2}{8} (V_{0})_{i} = \frac{15.2}{8} \times 6$
Finally only Si will work
$i = \frac{14.8}{8} (V_{0})_{f} = \frac{14.8}{8} \times 6$
Change $= \frac{0.4}{8} \times 6 = 0.3 V$

Q. Ge & Si diodes conduct at knee voltage 0.3V & 0.7V respectively. If Ge diode connection are reversed, then value of V0​ changes by xV , what is the value of 10x ?

Initially only Ge will work i=815.2​(V0​)i​=815.2​×6 Finally only Si will work i=814.8​(V0​)f​=814.8​×6 Change =80.4​×6=0.3V

Q. Ge & Si diodes conduct at knee voltage $0.3 V$ & $0.7 V$ respectively. If Ge diode connection are reversed, then value of $V_{0}$ changes by $x V$ , what is the value of $10 x$ ?

Initially only Ge will work $i = \frac{15.2}{8} (V_{0})_{i} = \frac{15.2}{8} \times 6$
Finally only Si will work
$i = \frac{14.8}{8} (V_{0})_{f} = \frac{14.8}{8} \times 6$
Change $= \frac{0.4}{8} \times 6 = 0.3 V$