One Faraday deposits one equivalent which also one gram atom for Na. (i) Na(l)++1e−→Na(s); (IF of electricity is required) Ba(l)2++2e−→Ba(s); (2F of electricity required) Cu(l)2++2e−→Cu(s); (2F of electricity is required) Al(l)3++3e−→Al(s); (3F of electricity is required)