From the ground, a projectile is fired at an angle of 60 degrees to the horizontal with a speed of 20 m/s-1. Take acceleration due to gravity as 10 m/s-2. The horizontal range of the projectile is

Question

From the ground, a projectile is fired at an angle of 60 degrees to the horizontal with a speed of 20 m/s-1. Take acceleration due to gravity as 10 m/s-2. The horizontal range of the projectile is (A) 10 √3 m  (B) 20 m (C) 20 √3 m  (D) 40 √3 m

Tardigrade Admin · Accepted Answer

The horizontal range R=(u2 sin 2 θ/g) Given, u=20 m / s θ=60° g=10 m / s 2 R=((20)2 sin (2 × 60°)/10) =(20 × 20/10) × (√3/2)=20 √3 m

Q. From the ground, a projectile is fired at an angle of $60$ degrees to the horizontal with a speed of $20 m / s^{- 1}$ . Take acceleration due to gravity as $10 m / s^{- 2}$ . The horizontal range of the projectile is

$103 m$

20 m

$203 m$

$403 m$

$4003 m$

The horizontal range
$R = \frac{u ^{2} s i n 2 θ}{g}$
Given, $u = 20 m / s$
$θ = 6 0^{\circ}$
$g = 10 m / s^{2}$
$R = \frac{( 20 ) ^{2} s i n ( 2 \times 6 0 ^{\circ} )}{10}$
$= \frac{20 \times 20}{10} \times \frac{3}{2} = 203 m$

Q. From the ground, a projectile is fired at an angle of 60 degrees to the horizontal with a speed of 20m/s−1. Take acceleration due to gravity as 10m/s−2. The horizontal range of the projectile is

103​m

20 m

203​m

403​m

4003​m