From the following graph of photocurrent against collector plate potential for two different intensities of light I1 and I2 , one can conclude

Question

From the following graph of photocurrent against collector plate potential for two different intensities of light I1 and I2 , one can conclude Question

(A) I1=I2 (B) I1>I2 (C) I1 < I2 (D) Comparison is not possible

Tardigrade Admin · Accepted Answer

The value of photocurrent depends on the intensity of incident light. Hence, when the intensity of incident light increases, then the value of photocurrent is increased. i.e.
the intensity of light

(I) \propto

photocurrent
Solution

From graph

I_{1} < I_{2}

Q. From the following graph of photocurrent against collector plate potential for two different intensities of light $I_{1}$ and $I_{2}$ , one can conclude

$I_{1} = I_{2}$

$I_{1} > I_{2}$

$I_{1} < I_{2}$

Comparison is not possible

The value of photocurrent depends on the intensity of incident light. Hence, when the intensity of incident light increases, then the value of photocurrent is increased. i.e.
the intensity of light $(I) \propto$ photocurrent

From graph
$I_{1} < I_{2}$

Q. From the following graph of photocurrent against collector plate potential for two different intensities of light I1​ and I2​ , one can conclude

I1​=I2​

I1​>I2​

I1​<I2​