Frame the formula: The square of the difference of p and q is equal to the sum of p2, q2 and (-2pq).

Question

Frame the formula: The square of the difference of p and q is equal to the sum of p2, q2 and (-2pq). (A) (p-q)2=p2+q2-2 p q (B) (p-q)2=p2+q2+2 p q (C) (p-q)2=p2-q2-2 p q (D) (p+q)2=p2+q2-2 p q

Tardigrade Admin · Accepted Answer

Correct answer is (a) (p-q)2=p2+q2-2 p q

Q. Frame the formula: The square of the difference of $p$ and $q$ is equal to the sum of $p^{2}, q^{2}$ and (-2pq).

$(p - q)^{2} = p^{2} + q^{2} - 2 pq$

$(p - q)^{2} = p^{2} + q^{2} + 2 pq$

$(p - q)^{2} = p^{2} - q^{2} - 2 pq$

$(p + q)^{2} = p^{2} + q^{2} - 2 pq$

Correct answer is (a) $(p - q)^{2} = p^{2} + q^{2} - 2 pq$

Q. Frame the formula: The square of the difference of p and q is equal to the sum of p2,q2 and (-2pq).

(p−q)2=p2+q2−2pq

(p−q)2=p2+q2+2pq

(p−q)2=p2−q2−2pq

(p+q)2=p2+q2−2pq