Four solutions of K2SO4 with the concentration 0.1m,0.01m,0.001m and 0.0001m are available. The maximum value of van't Hoff factor, i corresponds to:

Question

Four solutions of K2SO4 with the concentration 0.1m,0.01m,0.001m and 0.0001m are available. The maximum value of van't Hoff factor, i corresponds to: (A) 0.0001m solution (B) 0.001m solution (C) 0.01m solution (D) 0.1m solution

Tardigrade Admin · Accepted Answer

Basically, van't Hoff factor (i) propto (1/ textmolality (m)) So more the value of molality less will be the van't Hoff factor and less will be the value of molality more will be the van't Hoff factor. Also, degree of ionisation increases with dilution which leads to generation of more number of particles. So our answer is 0.0001 m solution because it has minimum value among these.

Q. Four solutions of $K_{2} S O_{4}$ with the concentration $0.1 m, 0.01 m, 0.001 m$ and $0.0001 m$ are available. The maximum value of van't Hoff factor, $i$ corresponds to:

$0.0001 m$ solution

$0.001 m$ solution

$0.01 m$ solution

$0.1 m$ solution

Q. Four solutions of K2​SO4​ with the concentration 0.1m,0.01m,0.001m and 0.0001m are available. The maximum value of van't Hoff factor, i corresponds to:

0.0001m solution

0.001m solution

0.01m solution

0.1m solution

Q. Four solutions of $K_{2} S O_{4}$ with the concentration $0.1 m, 0.01 m, 0.001 m$ and $0.0001 m$ are available. The maximum value of van't Hoff factor, $i$ corresponds to:

$0.0001 m$ solution

$0.001 m$ solution

$0.01 m$ solution

$0.1 m$ solution