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  3. Chemistry
  4. Four solutions of K2SO4 with the concentration 0.1m,0.01m,0.001m and 0.0001m are available. The maximum value of van't Hoff factor, i corresponds to:

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Q. Four solutions of $K_{2}SO_{4}$ with the concentration $0.1m,0.01m,0.001m$ and $0.0001m$ are available. The maximum value of van't Hoff factor, $i$ corresponds to:

NTA AbhyasNTA Abhyas 2022

Solution:

Basically, van't Hoff factor $\left(i\right) \propto \frac{1}{\text{molality} \left(m\right)}$
So more the value of molality less will be the van't Hoff factor and less will be the value of molality more will be the van't Hoff factor. Also, degree of ionisation increases with dilution which leads to generation of more number of particles.
So our answer is $0.0001\,m$ solution because it has minimum value among these.