Four persons P, Q, R and S are initially at the four corners of a square of side d. Each person now moves with a constant speed v in such a way that P always moves directly towards Q, Q towards R, R towards S, and S towards P. The four persons will meet after time

Question

Four persons P, Q, R and S are initially at the four corners of a square of side d. Each person now moves with a constant speed v in such a way that P always moves directly towards Q, Q towards R, R towards S, and S towards P. The four persons will meet after time (A) (d/2 v) (B) (d/v) (C) (3 d/2 v) (D) They will never meet

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/3f27e659c98d8d4d7c8837cd7ae62546-.png" /> T=(d/vr e l) vrel =v-v cos 90° =v-0 =v T=(d/v)

Q. Four persons $P, Q, R$ and $S$ are initially at the four corners of a square of side $d$ . Each person now moves with a constant speed $v$ in such a way that $P$ always moves directly towards $Q, Q$ towards $R, R$ towards $S$ , and $S$ towards $P$ . The four persons will meet after time

$\frac{d}{2 v}$

$\frac{d}{v}$

$\frac{3 d}{2 v}$

They will never meet

$T = \frac{d}{v _{re l}}$
$v_{re l} = v - v cos 9 0^{\circ}$
$= v - 0$
$= v$
$T = \frac{d}{v}$

Q. Four persons P,Q,R and S are initially at the four corners of a square of side d. Each person now moves with a constant speed v in such a way that P always moves directly towards Q,Q towards R,R towards S, and S towards P. The four persons will meet after time

2vd​

vd​

2v3d​