Four moles of PCl5 are heated in a closed 4 dm3 container to reach equilibrium at 400 K. at equilibrium 50% of PCl5 is dissociated. What is the value of textK textc in textmol/L for the dissociation of PCl5 into PCl3 and Cl2 at 400 K is

Question

Four moles of PCl5 are heated in a closed 4 dm3 container to reach equilibrium at 400 K. at equilibrium 50% of PCl5 is dissociated. What is the value of textK textc in textmol/L for the dissociation of PCl5 into PCl3 and Cl2 at 400 K is (A) 0.50 (B) 1.00 (C) 1.15 (D) 0.25

Tardigrade Admin · Accepted Answer

PCl5leftharpoons PCl3+Cl2 Initial conc. (4/4) 0 0 Equili. conc. (2/4) (2/4) (2/4) K=([P C l3] [C l2]/[P C l5]) =(2 × 2 × 4/4 × 4 × 2)=(1/2)=0.5

Q. Four moles of $PC l_{5}$ are heated in a closed $4 d m^{3}$ container to reach equilibrium at 400 K. at equilibrium 50% of $PC l_{5}$ is dissociated. What is the value of $K_{c}$ in $mol/L$ for the dissociation of $PC l_{5}$ into $PC l_{3}$ and $C l_{2}$ at 400 K is

0.50

1.00

1.15

0.25

$PC l_{5} ⇌ PC l_{3} + C l_{2}$

Initial conc. $\frac{4}{4}$ 0 0

Equili. conc. $\frac{2}{4} \frac{2}{4} \frac{2}{4}$

$K = \frac{[ PC l _{3} ] [ C l _{2} ]}{[ PC l _{5} ]}$

$= \frac{2 \times 2 \times 4}{4 \times 4 \times 2} = \frac{1}{2} = 0.5$

Q. Four moles of PCl5​ are heated in a closed 4dm3 container to reach equilibrium at 400 K. at equilibrium 50% of PCl5​ is dissociated. What is the value of Kc​ in mol/L for the dissociation of PCl5​ into PCl3​ and Cl2​ at 400 K is