Four light sources produce the following four waves: y 1= a sin (ω t+φ1) y2=a sin 2 ω t y3=a' sin (ω t+φ2) y 4= a' sin (3 ω t+φ) Superposition of which two waves give rise to interference?

Question

Four light sources produce the following four waves: y 1= a sin (ω t+φ1) y2=a sin 2 ω t y3=a' sin (ω t+φ2) y 4= a' sin (3 ω t+φ) Superposition of which two waves give rise to interference? (A) (i) and (ii) (B) (ii) and (iii) (C) (i) and (iii) (D) (iii) and (iv

Tardigrade Admin · Accepted Answer

Interference phenomenon takes place between two waves which have equal frequency and propagate in same direction.
Hence,

y_{1} = a sin (ω t + ϕ_{1})

y_{3} = a^{^{'}} sin (ω t + ϕ_{2})

will give rise to interference as the two waves have same frequency

ω

.

Q. Four light sources produce the following four waves: y1​=asin(ωt+ϕ1​) y2​=asin2ωt y3​=a′sin(ωt+ϕ2​) y4​=a′sin(3ωt+ϕ) Superposition of which two waves give rise to interference?

(i) and (ii)

(ii) and (iii)

(i) and (iii)

(iii) and (iv

Interference phenomenon takes place between two waves which have equal frequency and propagate in same direction. Hence,y1​=asin(ωt+ϕ1​) y3​=a′sin(ωt+ϕ2​) will give rise to interference as the two waves have same frequency ω.

Q. Four light sources produce the following four waves:
$y_{1} = a sin (ω t + ϕ_{1})$
$y_{2} = a sin 2 ω t$
$y_{3} = a^{'} sin (ω t + ϕ_{2})$
$y_{4} = a^{'} sin (3 ω t + ϕ)$
Superposition of which two waves give rise to interference?

Interference phenomenon takes place between two waves which have equal frequency and propagate in same direction.
Hence, $y_{1} = a sin (ω t + ϕ_{1})$
$y_{3} = a^{^{'}} sin (ω t + ϕ_{2})$
will give rise to interference as the two waves have same frequency $ω$ .