Four atoms of hydrogen combine to form an 24 He atom with a release of energy of

Question

Four atoms of hydrogen combine to form an 24 He atom with a release of energy of (A) 26.7 MeV (B) 216 MeV (C) 3.27 MeV (D) 1 MeV

Tardigrade Admin · Accepted Answer

The fusion reaction in the sun is a multi-step process in which hydrogen is burned into helium, hydrogen being the fuel and helium the ashes. The proton-proton

(p, p)

cycle by which this occurs is represented by the following sets of reactions:

_{1}^{1} H +_{1}^{1} H \to_{1}^{2} H + e^{+} + v + 0.42 M e V \dots

(i)

e^{+} + e^{-} \to γ + γ + 1.02 M e V \dots

(ii)

_{1}^{2} H +_{1}^{1} H \to_{2}^{3} He + γ + 5.49 M e V \dots

(iii)

_{2}^{3} He +_{2}^{3} He \to_{2}^{4} He +_{1}^{1} H +_{1}^{1} H + 12.86 M e V \dots

(iv)
For the fourth reaction to occur, the first three reactions must occur twice, in which case two light helium nuclei unite to form ordinary helium or nucleus. If we consider the combination

2 (i) + 2 (ii) + 2 (iii) + (i v)

, the net effect is

4_{1}^{1} H + 2 e^{-} \to_{2}^{4} He + 2 v + 6 γ + 26.7 M e V

Q. Four atoms of hydrogen combine to form an 24​He atom with a release of energy of

26.7 MeV

216 MeV

3.27 MeV

1 MeV

Q. Four atoms of hydrogen combine to form an $_{2}^{4} He$ atom with a release of energy of