Four 2 kg masses are connected by (1/4) m spokes to an axle. A force of 24 N acts on a lever 1 / 2 m long to produce angular acceleration α . The magnitude of α in rad s -2 is

Question

Four 2 kg masses are connected by (1/4) m spokes to an axle. A force of 24 N acts on a lever 1 / 2 m long to produce angular acceleration α . The magnitude of α in rad s -2 is (A) 24 (B) 12 (C) 6 (D) 3

Tardigrade Admin · Accepted Answer

As, Force × distance =τ=I α ⇒ F sin 30° × (1/2)=4[2 ×((1/4))2] α or 24 × (1/2) × (1/2)=(α/2) ∴ α=12 rad s -2

Q. Four $2 k g$ masses are connected by $\frac{1}{4} m$ spokes to an axle. A force of $24 N$ acts on a lever $1/2 m$ long to produce angular acceleration $α .$ The magnitude of $α$ in $r a d s^{- 2}$ is

24

12

6

3

As, Force $\times$ distance $= τ = I α$
$\Rightarrow F sin 3 0^{\circ} \times \frac{1}{2} = 4 [2 \times (\frac{1}{4})^{2}] α$
or $24 \times \frac{1}{2} \times \frac{1}{2} = \frac{α}{2}$
$∴ α = 12 r a d s^{- 2}$

Q. Four 2kg masses are connected by 41​m spokes to an axle. A force of 24N acts on a lever 1/2m long to produce angular acceleration α. The magnitude of α in rads−2 is

24

12

6

3

As, Force × distance =τ=Iα ⇒Fsin30∘×21​=4[2×(41​)2]α or 24×21​×21​=2α​ ∴α=12rads−2

Q. Four $2 k g$ masses are connected by $\frac{1}{4} m$ spokes to an axle. A force of $24 N$ acts on a lever $1/2 m$ long to produce angular acceleration $α .$ The magnitude of $α$ in $r a d s^{- 2}$ is

As, Force $\times$ distance $= τ = I α$
$\Rightarrow F sin 3 0^{\circ} \times \frac{1}{2} = 4 [2 \times (\frac{1}{4})^{2}] α$
or $24 \times \frac{1}{2} \times \frac{1}{2} = \frac{α}{2}$
$∴ α = 12 r a d s^{- 2}$