Forces of 100 N each are applied in opposite directions on the upper and lower faces of a cube of side 20 cm. The upper face is shifted parallel to itself by 0.25 cm. If the side of the cube were 10 cm, then the displacement would be

Question

Forces of 100 N each are applied in opposite directions on the upper and lower faces of a cube of side 20 cm. The upper face is shifted parallel to itself by 0.25 cm. If the side of the cube were 10 cm, then the displacement would be (A) 0.25 cm (B) 0.5 cm (C) 0.75 cm (D) 1 cm

Tardigrade Admin · Accepted Answer

As , η=(F I/A Δ l)=(F I/l2 Δ l)=(F/l Δ l) or Δ l propto (1/l) (for, F= constant ) If l is halved, then Δ l is doubled.

Q. Forces of $100 N$ each are applied in opposite directions on the upper and lower faces of a cube of side $20 c m$ . The upper face is shifted parallel to itself by $0.25 c m$ . If the side of the cube were $10 c m$ , then the displacement would be

0.25 cm

0.5 cm

0.75 cm

1 cm

$A s, η = \frac{F I}{A Δ l} = \frac{F I}{l ^{2} Δ l} = \frac{F}{l Δ l}$ or $Δ l \propto \frac{1}{l}$ (for, $F =$ constant $)$
If $l$ is halved, then $Δ l$ is doubled.

Q. Forces of 100N each are applied in opposite directions on the upper and lower faces of a cube of side 20cm. The upper face is shifted parallel to itself by 0.25cm. If the side of the cube were 10cm, then the displacement would be