Forces 5 N, 12 N and 13 N are in equilibrium. If sin text 23° =(5/13), the angle between 5 N force and 13 N force is

Question

Forces 5 N, 12 N and 13 N are in equilibrium. If sin text 23° =(5/13), the angle between 5 N force and 13 N force is (A)  23°  (B)  67°  (C)  90°  (D)  113°

Tardigrade Admin · Accepted Answer

As 52+122=132, so these forces will be acting along the sides of a right angled triangle. Angle between 5 N and 13 N =180-(90+23) =180-113=67o

Q. Forces 5 N, 12 N and 13 N are in equilibrium. If $s in 23^{\circ} = \frac{5}{13},$ the angle between 5 N force and 13 N force is

$23^{\circ}$

$67^{\circ}$

$90^{\circ}$

$113^{\circ}$

As $5^{2} + 12^{2} = 13^{2},$ so these forces will be acting along the sides of a right angled triangle. Angle between 5 N and 13 N

$= 180 - (90 + 23)$
$= 180 - 113 = 67^{o}$

Q. Forces 5 N, 12 N and 13 N are in equilibrium. If sin23∘=135​, the angle between 5 N force and 13 N force is

23∘

67∘

90∘

113∘