Question

Forces 5 N, 12 N and 13 N are in equilibrium. If $ sin\text{ }23{}^\circ =\frac{5}{13}, $ the angle between 5 N force and 13 N force is

• A. $ 23{}^\circ $
• B. $ 67{}^\circ $
• C. $ 90{}^\circ $
• D. $ 113{}^\circ $

Answer 1

Answer: (B)

As $ {{5}^{2}}+{{12}^{2}}={{13}^{2}}, $ so these forces will be acting along the sides of a right angled triangle. Angle between 5 N and 13 N
$=180-(90+23) $
$=180-113={{67}^{o}} $