Force of 10N is applied tangentially on a disc of mass 2kg and radius 1m , which is free to rotate on its geometric axis then angular velocity of disc after 2seconds is :-

Question

Force of 10N is applied tangentially on a disc of mass 2kg and radius 1m , which is free to rotate on its geometric axis then angular velocity of disc after 2seconds is :- (A) 10rads- 1 (B) 20rads- 1 (C) 5rads- 1 (D) 40rads- 1

Tardigrade Admin · Accepted Answer

For Disc τ=R× F=Iα Here (I = (M R2/2)) 1× 10=(2 × 1/2)× α α =10rads- 2 then ω =ω 0+α t =0+10× 2 =20rads- 1

Q. Force of $10 N$ is applied tangentially on a disc of mass $2 k g$ and radius $1 m$ , which is free to rotate on its geometric axis then angular velocity of disc after $2 seco n d s$ is :-

$10 r a d s^{- 1}$

$20 r a d s^{- 1}$

$5 r a d s^{- 1}$

$40 r a d s^{- 1}$

For Disc $τ = R \times F = I α$
Here $(I = \frac{M R ^{2}}{2})$
$1 \times 10 = \frac{2 \times 1}{2} \times α$
$α = 10 r a d s^{- 2}$
then $ω = ω_{0} + α t$
$= 0 + 10 \times 2$
$= 20 r a d s^{- 1}$

Q. Force of 10N is applied tangentially on a disc of mass 2kg and radius 1m , which is free to rotate on its geometric axis then angular velocity of disc after 2seconds is :-

10rads−1

20rads−1

5rads−1

40rads−1