Question

For $Z{n}^{2+}$ |Zn, $E^{\circ }$ = - 0.76 V then EMF of the cell
$Zn/Z{n}^{2+}$ (1M)|2H⁺ (1M)| $H_2(1atm)$ will be

• A. - 0.76 V
• B. 0.76 V
• C. 0.38 V
• D. - 0.38 V

Answer 1

Answer: (B)

$E_{cell}^{\circ }=E_{right}^{\circ }-E_{left}^{\circ }$
$E_{cell}^{\circ }=0-\left(0-0.76\right)=0.76V$