Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
For z = a 2 x 3 y (1/2), where ' a ' is a constant. If percentage error in measurement of ' x ' and ' y ' are 4 % and 12 %, respectively, then the percentage error for ' z ' will be %.
Q. For
z
=
a
2
x
3
y
2
1
, where '
a
' is a constant. If percentage error in measurement of '
x
' and '
y
' are
4%
and
12%
, respectively, then the percentage error for '
z
' will be
%
.
1412
155
JEE Main
JEE Main 2022
Physical World, Units and Measurements
Report Error
Answer:
18
Solution:
z
=
a
2
x
3
y
1/2
z
Δ
z
=
a
2Δ
a
+
x
3Δ
x
+
2
1
y
Δ
y
a
is constant
z
Δ
z
×
100
=
3
(
4%
)
+
2
1
(
12%
)
=
18%