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Tardigrade
Question
Mathematics
For θ > (π/3), the value of f(θ)= sec 2 θ+ cos 2 θ always lies in the
Q. For
θ
>
3
π
, the value of
f
(
θ
)
=
sec
2
θ
+
cos
2
θ
always lies in the
518
161
Manipal
Manipal 2019
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A
(
0
,
2
)
B
(
0
,
2
)
[
0
,
1
]
C
(
1
,
2
)
D
[
2
,
∞
)
Solution:
We have,
f
(
θ
)
=
sec
2
θ
+
cos
2
θ
Since AM
≥
GM
⇒
2
s
e
c
2
θ
+
c
o
s
2
θ
≥
(
sec
2
θ
⋅
cos
2
θ
)
1/2
⇒
2
s
e
c
2
θ
+
c
o
s
2
θ
≥
1
⇒
2
s
e
c
2
θ
+
c
o
s
2
θ
≥
2
⇒
f
(
θ
)
≥
2
∴
The value of
f
(
θ
)
always lies in the interval
[
2
,
∞
)
.