Question

For the transformation, ${}_7{N}^{14}+...\to {}_6{C}^{14}+{}_1{H}^1$ the bombarding particle is:

• A. proton
• B. neutron
• C. deuteron
• D. electron

Answer 1

Answer: (B)

The balanced reaction is, ${}_7{N}^{14}+{}_0{n}^1\to {}_6{C}^{14}+{}_1{H}^1$ Hence, the bombarding particle is neutron.