1. Tardigrade
  2. Question
  3. Chemistry
  4. For the transformation, 7N14+... xrightarrow6C14+1H1 the bombarding particle is:

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Q. For the transformation, $ {}_{7}{{N}^{14}}+...\xrightarrow{{}}{}_{6}{{C}^{14}}+{}_{1}{{H}^{1}} $ the bombarding particle is:

JIPMERJIPMER 1996

Solution:

The balanced reaction is, $ {}_{7}{{N}^{14}}+{}_{0}{{n}^{1}}\xrightarrow{{}}{}_{6}{{C}^{14}}+{}_{1}{{H}^{1}} $ Hence, the bombarding particle is neutron.