Question

For the system shown in the figure, the inclined plane is fixed, all the pulleys are light and friction is absent everywhere. The tension in the string will be

• A. $\frac{2}{3}mgsin\theta$
• B. $\frac{3}{2}mgsin\theta$
• C. $\frac{1}{2}mgsin\theta$
• D. 2 $mgsin\theta$

Answer 1

Answer: (C)

From free body diagram, we get
$mgsin\theta -T=ma$
$T=ma$


$\therefore mgsin\theta -T=T$
or $2T=mgsin\theta$ or $T=\frac{1}{2}mgsin\theta$