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Q. For the system shown in the figure, the inclined plane is fixed, all the pulleys are light and friction is absent everywhere. The tension in the string will be



Question

NTA AbhyasNTA Abhyas 2020Laws of Motion

Solution:

From free body diagram, we get
$mgsin \theta - T = m a$
$T=ma$

Solution
$\therefore \, mgsin \theta - T = T$
or $2T=mgsin \theta $ or $T=\frac{1}{2}mgsin \theta $