For the square planar complex [M(a)(b)(c)(d)] (where, M = central metal and a, b, c and d are monodentate ligands), the number of possible geometrical isomers are

Question

For the square planar complex [M(a)(b)(c)(d)] (where, M = central metal and a, b, c and d are monodentate ligands), the number of possible geometrical isomers are (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

For [M [a][b][c][d]] square planar complex, the number of possible geometrical isomers is three which is obtained by fixing the position of one of the ligands say a while the other ligands b, c and d are placed trans to it.

Q. For the square planar complex $[M (a) (b) (c) (d)]$ (where, $M =$ central metal and $a, b, c$ and $d$ are monodentate ligands), the number of possible geometrical isomers are

1

2

3

4

For $[M [a] [b] [c] [d]]$ square planar complex, the number of possible geometrical isomers is three which is obtained by fixing the position of one of the ligands say $a$ while the other ligands $b, c$ and $d$ are placed trans to it.

Q. For the square planar complex [M(a)(b)(c)(d)] (where, M= central metal and a,b,c and d are monodentate ligands), the number of possible geometrical isomers are

1

2

3

4

For [M[a][b][c][d]] square planar complex, the number of possible geometrical isomers is three which is obtained by fixing the position of one of the ligands say a while the other ligands b,c and d are placed trans to it.

Q. For the square planar complex $[M (a) (b) (c) (d)]$ (where, $M =$ central metal and $a, b, c$ and $d$ are monodentate ligands), the number of possible geometrical isomers are

For $[M [a] [b] [c] [d]]$ square planar complex, the number of possible geometrical isomers is three which is obtained by fixing the position of one of the ligands say $a$ while the other ligands $b, c$ and $d$ are placed trans to it.