For the series LCR circuit shown in the figure, what is the resonance frequency and the amplitude of the current at the resonating frequency?

Question

For the series LCR circuit shown in the figure, what is the resonance frequency and the amplitude of the current at the resonating frequency? (A)  2500 rad-s-1and 5√2A  (B)  2500 text rad-s-1and text 5 text A  (C)  2500 text rad-s-1and (5/√2) text A  (D)  250 rad-s-1and 5√2A

Tardigrade Admin · Accepted Answer

Resonance frequency, ω =(1/√LC) =(1/√8× 10-3× 20× 10-6) =(1/4× 10-4)=(104/4) ≈ 2500 rad/s Amplitude of current, I0=(V/R)=(220/44) =5A

Q. For the series $L CR$ circuit shown in the figure, what is the resonance frequency and the amplitude of the current at the resonating frequency?

$2500 r a d - s^{- 1} an d 52 A$

$2500 r a d - s^{- 1} an d 5 A$

$2500 r a d - s^{- 1} an d \frac{5}{2} A$

$250 r a d - s^{- 1} an d 52 A$

$25 r a d - s^{- 1} an d 52 A$

Resonance frequency, $ω = \frac{1}{L C}$
$= \frac{1}{8 \times 10 ^{- 3} \times 20 \times 10 ^{- 6}}$
$= \frac{1}{4 \times 10 ^{- 4}} = \frac{10 ^{4}}{4}$
$\approx 2500 r a d / s$ Amplitude of current, $I_{0} = \frac{V}{R} = \frac{220}{44}$
$= 5 A$

Q. For the series LCR circuit shown in the figure, what is the resonance frequency and the amplitude of the current at the resonating frequency?

2500rad−s−1and52​A

2500rad−s−1and5A

2500rad−s−1and2​5​A

250rad−s−1and52​A

25rad−s−1and52​A

Resonance frequency, ω=LC​1​ =8×10−3×20×10−6​1​ =4×10−41​=4104​ ≈2500rad/s Amplitude of current, I0​=RV​=44220​ =5A