For the resistance network shown in the figure, choose the correct option(s)

Question

For the resistance network shown in the figure, choose the correct option(s) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d7557338224b779844f6a6c40b305b77-.png" /> (A) The current through PQ is zero. (B) I 1=3 A (C) The potential at S is less than that at Q. (D) I 2=2 A

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7753900d6a86bc506c74f2cb7391402a-.png" /> Nodes P and Q are equipotential and nodes S and T are equipotential from wheatstone bridge, no current passes through PQ and ST. I1=(12/4)=3 A I2= I 1((12/6+12))=2 A

Q. For the resistance network shown in the figure, choose the correct option(s)

The current through $PQ$ is zero.

$I_{1} = 3 A$

The potential at $S$ is less than that at $Q$ .

$I_{2} = 2 A$

Nodes $P$ and $Q$ are equipotential and nodes $S$
and $T$ are equipotential from wheatstone bridge,
no current passes through $PQ$ and $ST$ .
$I_{1} = \frac{12}{4} = 3 A$
$I_{2} = I_{1} (\frac{12}{6 + 12}) = 2 A$

Q. For the resistance network shown in the figure, choose the correct option(s)

The current through PQ is zero.

I1​=3A

The potential at S is less than that at Q.

I2​=2A

Nodes P and Q are equipotential and nodes S and T are equipotential from wheatstone bridge, no current passes through PQ and ST. I1​=412​=3A I2​=I1​(6+1212​)=2A

The current through $PQ$ is zero.

$I_{1} = 3 A$

The potential at $S$ is less than that at $Q$ .

$I_{2} = 2 A$

Nodes $P$ and $Q$ are equipotential and nodes $S$
and $T$ are equipotential from wheatstone bridge,
no current passes through $PQ$ and $ST$ .
$I_{1} = \frac{12}{4} = 3 A$
$I_{2} = I_{1} (\frac{12}{6 + 12}) = 2 A$