For the redox reaction, xMnO4-+yH2C2O4+zH+ arrow mMn2 ++nCO2+pH the value of x, y, m and n are respectively

Question

For the redox reaction, xMnO4-+yH2C2O4+zH+ arrow mMn2 ++nCO2+pH the value of x, y, m and n are respectively (A) 10, 2, 5, 2 (B) 2, 5, 2, 10 (C) 6, 4, 2, 4 (D) 3, 5, 2, 10

Tardigrade Admin · Accepted Answer

The balanced reaction is gives as 2MnO4-+5H2C2O4+6H+ arrow 2Mn2 ++10CO2+8H2O Thus, x=2,y=5,m=2 and n=10

Q. For the redox reaction,

$x M n O_{4}^{-} + y H_{2} C_{2} O_{4} + z H^{+} \to m M n^{2 +} + n C O_{2} + p H$

the value of x, y, m and n are respectively

10, 2, 5, 2

2, 5, 2, 10

6, 4, 2, 4

3, 5, 2, 10

The balanced reaction is gives as

$2 M n O_{4}^{-} + 5 H_{2} C_{2} O_{4} + 6 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O$

Thus, $x = 2, y = 5, m = 2$ and $n = 10$

Q. For the redox reaction, xMnO4−​+yH2​C2​O4​+zH+→mMn2++nCO2​+pH the value of x, y, m and n are respectively