For the redox reaction MnO-4 + C2 O2-4 + H+ → Mn2+ + CO2 + H2 O the correct coefficients of the reactants for the balanced equation are

Question

For the redox reaction MnO-4 + C2 O2-4 + H+ → Mn2+ + CO2 + H2 O the correct coefficients of the reactants for the balanced equation are (A) MnO 4-⟶5, C 2 O 42-⟶16, H + ⟶2 (B) MnO 4-⟶16, C 2 O 42-⟶5, H + ⟶2 (C) MnO 4-⟶2, C 2 O 42-⟶16, H + ⟶5 (D) MnO 4-⟶2, C 2 O 42-⟶5, H + ⟶16

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6169f6dd77b75a9babf9a678587f1f9f-.png" /> n -factor of MnO 4- ⇒ 5 n -factor of C 2 O 42- ⇒ 2 Ratio of n-factors of MnO 4- and C 2 O 42- is 5: 2 So, molar ratio in balanced reaction is 2: 5 ∴ The balanced equation is

Q. For the redox reaction
$M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$
the correct coefficients of the reactants for the balanced equation are

$M n O_{4}^{-} ⟶ 5, C_{2} O_{4}^{2 -} ⟶ 16, H^{+} ⟶ 2$

$M n O_{4}^{-} ⟶ 16, C_{2} O_{4}^{2 -} ⟶ 5, H^{+} ⟶ 2$

$M n O_{4}^{-} ⟶ 2, C_{2} O_{4}^{2 -} ⟶ 16, H^{+} ⟶ 5$

$M n O_{4}^{-} ⟶ 2, C_{2} O_{4}^{2 -} ⟶ 5, H^{+} ⟶ 16$

$n$ -factor of $M n O_{4}^{-} \Rightarrow 5$

$n$ -factor of $C_{2} O_{4}^{2 -} \Rightarrow 2$

Ratio of n-factors of $M n O_{4}^{-}$ and $C_{2} O_{4}^{2 -}$ is $5 : 2$

So, molar ratio in balanced reaction is $2 : 5$

$∴$ The balanced equation is

Q. For the redox reaction MnO4−​+C2​O42−​+H+→Mn2++CO2​+H2​O the correct coefficients of the reactants for the balanced equation are

MnO4−​⟶5,C2​O42−​⟶16,H+⟶2

MnO4−​⟶16,C2​O42−​⟶5,H+⟶2

MnO4−​⟶2,C2​O42−​⟶16,H+⟶5

MnO4−​⟶2,C2​O42−​⟶5,H+⟶16