Question

For the redox reaction
$MnO^{-}_4 + C_2 O^{2-}_4 + H^{+} \to Mn^{2+} + CO_2 + H_2 O $
the correct coefficients of the reactants for the balanced equation are

• A. $MnO _{4}^{-}⟶5, C _{2} O _{4}^{2-}⟶16, H ^{+} ⟶2$
• B. $MnO _{4}^{-}⟶16, C _{2} O _{4}^{2-}⟶5, H ^{+} ⟶2$
• C. $MnO _{4}^{-}⟶2, C _{2} O _{4}^{2-}⟶16, H ^{+} ⟶5$
• D. $MnO _{4}^{-}⟶2, C _{2} O _{4}^{2-}⟶5, H ^{+} ⟶16$

Answer 1

Answer: (D)

$n$ -factor of $MnO _{4}^{-} \Rightarrow 5$

$n$ -factor of $C _{2} O _{4}^{2-} \Rightarrow 2$

Ratio of n-factors of $MnO _{4}^{-}$ and $C _{2} O _{4}^{2-}$ is $5: 2$

So, molar ratio in balanced reaction is $2: 5$

$\therefore $The balanced equation is